A rigid disk spinning near the speed of light has its rim Lorentz contracted but not its radius; is the...
physics/ehrenfest.paradox New
New entry, edited from material collected for the archive and not yet in a released version.
Problem
A rigid disk spinning near the speed of light has its rim Lorentz contracted but not its radius; is the ratio of circumference to diameter then no longer pi? Imagine a massless rigid disk whose circumference is painted with stripes, each stripe a meter long. Lets say there are 100 stripes around so the radius of the disk is 100m/2PI. Now spin the disk, so that the edge is close to c. In the stationary frame, each stripe shrinks according to Lorentz, and the radius stays the same since its distance is transverse to the velocity at every point. Yet if you take a picture from above, there are still 100 stripes. So in the picture the ratio of circumference to diameter is no longer PI. :-) -- Dave Ring <dwr2560@tam2000.tamu.edu>
Show solution
First, this 'puzzle' is so difficult that the cumulative faculties of sci.physics failed to come to a satisfactory conclusion last time I saw it there. It is known as Ehrenfest's paradox. Consider the simpler case of an infinite massless rigid pole, painted with stripes, each a meter long. Imagine accelerating the pole by attaching a rocket at each stripe. It is easy to see that each stripe must remain the same length. (This is analogous to the circumference remaining PI*R) On the other hand, we know that each segment must shrink according to Lorentz. This is indeed a contradiction, and the only way out is to complain about one of the two idealizations: infinite length, or infinite rigidity. I can make the pole as long as I want, so the problem is infinite rigidity. The segments do indeed remain constant, and in the moving frame, the segments are _stretched_. Similarly, the rotating disk cannot be infinitely rigid. In fact there is a more direct problem with infinite rigidity, the speed of sound in the material is greater than the speed of light. A related, and somewhat more subtle paradox occurs when we examine what happens to a rapidly rotating ring of high tensile strength. One would imagine it would want to shrink due to the stretching effect. But intuitively, the 'gravitational force' in the rotating frame is outward only. It seems strange that the ring should get smaller as you increase the outward force. It turns out the intuitive answer is correct, the ring does not shrink. Obpuzzle: explain what's wrong with the other argument. Hint: a quantitative solution is not necessary. Boulware worked it out in the sixties. -- Dave Ring <dwr2560@tam2000.tamu.edu> [ Editor: "the circumference remaining PI*R" presumably means 2*PI*R; the stripes total 100 m = 2*PI*R for the stated radius 100m/2PI. ]