Complete the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 53, 371, ...

This is a finite sequence.  The next (and last) two entries are 5141
and 99481.

The sequence consist of those base 10 numbers whose digits are reversed
when converted to base 16.  For example, 99481 (base 10) is equal to
18499 (base 16).

There are no such numbers with more than five digits.  This is because
if N has k decimal digits then 10^(k-1) <= N < 10^k, and if N has k
hex digits then 16^(k-1) <= N < 16^k.  But 16^(k-1) > 10^k for k > 5.

-- David G Radcliffe <radcliff@alpha2.csd.uwm.edu>